IAE Academy

GATE BT

Enzymes

Classification, catalysis, kinetics and inhibition

Enzymes are biological catalysts, mostly proteins, that speed up reactions by stabilising the transition state without changing the equilibrium. For GATE BT you must classify enzymes by the six EC classes, apply the Michaelis-Menten equation, and read competitive, non-competitive, uncompetitive and mixed inhibition from apparent Km and Vmax or from Lineweaver-Burk plots. You must also recognise how allosteric and covalent regulation change the shape of the rate curve.

6 previous-year questions · 6 solved · 5 practice questions

Classification, active site and cofactors

An enzyme speeds up a reaction by lowering its activation energy (). It does not change of the reaction or its equilibrium constant, so it speeds the forward and reverse reactions by the same factor. Substrate binds in the active site, a cleft formed by a few residues that may be far apart in the primary sequence. Specificity comes from shape, charge, hydrogen bonding and hydrophobic contacts in the site. The lock-and-key model treats the site as a rigid shape complementary to the substrate. The induced-fit model, which describes most enzymes better, says that substrate binding changes the shape of the site so that the catalytic groups are brought into position.

The six EC classes (EC number = class.subclass.sub-subclass.serial)

Class (EC)

Reaction type

Example

1 Oxidoreductases

Oxidation-reduction: transfer of electrons, hydrogen atoms or hydride

Lactate dehydrogenase

2 Transferases

Transfer of a functional group (phosphate, amino, methyl) from one molecule to another

Hexokinase, aminotransferases

3 Hydrolases

Cleavage of a bond by addition of water

Trypsin, lipase, amylase

4 Lyases

Cleavage or formation of a bond by means other than hydrolysis or oxidation, often leaving or adding a double bond

Fumarase, aldolase

5 Isomerases

Rearrangement within one molecule

Triose phosphate isomerase, glucose 6-phosphate isomerase

6 Ligases

Joining of two molecules, coupled to ATP (or similar) hydrolysis

DNA ligase, pyruvate carboxylase

Since 2018 the EC list also has a seventh class, translocases (EC 7), which catalyse the movement of ions or molecules across a membrane. The six classes above are the classical set.

Many enzymes need a non-protein partner. A cofactor is a metal ion (Zn, Mg, Fe/Fe) or an organic coenzyme. A coenzyme bound loosely acts as a co-substrate (for example NAD). One bound tightly or covalently is a prosthetic group (for example heme, biotin, FAD in many enzymes). The protein part alone is the apoenzyme; the complete active enzyme is the holoenzyme. Many coenzymes come from vitamins: NAD and NADP from niacin (redox), FAD and FMN from riboflavin (redox), coenzyme A from pantothenate (acyl transfer), thiamine pyrophosphate from thiamine (decarboxylation), and pyridoxal phosphate from pyridoxine (transamination). Biotin (carboxylation) is itself a vitamin.

EXAM TIP

A catalyst changes only the rate of approach to equilibrium. If a question suggests an enzyme shifts the equilibrium or changes the standard free energy of the overall reaction, the statement is false.

Catalytic strategies

Enzymes use a small set of strategies, often several at once. The central idea behind all of them is that the enzyme binds the transition state more tightly than it binds the substrate, which lowers the activation energy.

Catalytic strategies

Strategy

How it works

Example

Acid-base catalysis

Side chains (His, Asp, Glu, Lys, Cys, Tyr) donate or accept protons at the right moment

RNase A (two His residues), chymotrypsin (His)

Covalent catalysis

A nucleophilic group on the enzyme forms a transient covalent bond with the substrate, giving a new, lower-energy pathway

Serine proteases (Ser), cysteine proteases (Cys)

Metal-ion catalysis

A bound metal ion orients substrate, stabilises negative charge, or generates a nucleophile (for example a Zn-bound hydroxide)

Carbonic anhydrase (Zn), many kinases (Mg)

Proximity and orientation

Binding brings reacting groups close together and in the correct orientation, so the effective concentration rises sharply

Almost all enzymes

Transition-state stabilisation (strain)

The site is complementary to the transition state; substrate may be distorted toward it

Lysozyme, and transition-state analogues as potent inhibitors

Chymotrypsin uses several of these strategies together. Its catalytic triad is Ser195, His57 and Asp102. Asp102 holds His57 in place, His57 acts as a general base that takes the proton from Ser195, and the activated Ser195 attacks the carbonyl carbon of the peptide bond (covalent catalysis), forming an acyl-enzyme. The negatively charged tetrahedral intermediate is stabilised by hydrogen bonds in the oxyanion hole (transition-state stabilisation). Water then hydrolyses the acyl-enzyme and the second product is released.

EXAM TIP

A transition-state analogue binds an enzyme far more tightly than the substrate does. This is evidence that the site is complementary to the transition state and not to the substrate.

Michaelis-Menten kinetics

For a single-substrate reaction , the model assumes: (1) the rate is measured as the initial velocity, when product is negligible and the reverse step can be ignored; (2) , so free is effectively the total and stays constant during the measurement; (3) the steady-state assumption, , which holds after a very short transient. When the rate is first order in . When the enzyme is saturated and the rate becomes zero order, approaching .

STEADY-STATE CONCENTRATION OF ES

From the steady-state balance . Multiplying by gives the Michaelis-Menten equation with .

MICHAELIS-MENTEN EQUATION

Initial velocity of a single-substrate enzyme under steady state with . is in concentration units (mM or M), in concentration per time (for example M/min).

MICHAELIS CONSTANT

For . equals the substrate concentration at which . It equals the dissociation constant of ES only if .

MAXIMUM VELOCITY AND TURNOVER NUMBER

(units s) is the number of substrate molecules converted per active site per second at saturation. For the simple mechanism above .

CATALYTIC EFFICIENCY

Units Ms. It is the apparent second-order rate constant at , where . Its upper limit is set by diffusion, about to Ms.

FRACTION OF VMAX REACHED AT A GIVEN [S]

For example gives , and gives .

Enzyme activity units. One international unit (U) is the amount of enzyme that converts 1 mol of substrate per minute under stated conditions. The SI unit is the katal (kat), 1 mol of substrate per second, so 1 U mol s nkat. Specific activity is units per mg of total protein. It rises during purification as other proteins are removed, and fold purification specific activity after a step specific activity of the crude extract.

Activity also depends on pH and temperature. A pH-activity curve is usually bell-shaped, because the groups that bind substrate and catalyse the reaction must be in the right ionisation state. Activity rises with temperature until the protein starts to denature, which gives an apparent temperature optimum that depends on how long the assay runs.

EXAM TIP

is a property of an enzyme with a particular substrate under given conditions (pH, temperature). It does not depend on , whereas does. A smaller means half-saturation at lower , which often (not always) means tighter binding.

Linear plots

Rearranging the rate equation gives straight lines from which and are read. The double-reciprocal (Lineweaver-Burk) plot is the one most often used to identify the type of inhibition. It distorts errors, though: the low- points lie far out at large , where small errors in become large errors in and dominate the fitted line, while the high- points crowd together near the y-axis.

LINEWEAVER-BURK (DOUBLE RECIPROCAL)

Plot against : slope , y-intercept , x-intercept .

EADIE-HOFSTEE

Plot against : slope , y-intercept , x-intercept .

HANES-WOOLF

Plot against : slope , y-intercept , x-intercept .

WORKED EXAMPLE

Initial rates of an enzyme (total enzyme 2 nM) give a Lineweaver-Burk line with y-intercept and x-intercept . Find , and .

Solution
  1. y-intercept , so .

  2. x-intercept , so mM.

  3. .

Answer: M/min, mM, s.

Reversible inhibition

A reversible inhibitor binds non-covalently, and activity returns when it is removed (for example by dialysis or dilution). Competitive inhibitors bind the free enzyme, usually at the active site and usually resembling the substrate, so substrate and inhibitor exclude each other. Uncompetitive inhibitors bind only the ES complex. Mixed inhibitors bind a site other than the active site and can bind both and , with different affinities. Pure non-competitive inhibition is the special case of mixed inhibition in which the affinities for and are equal. Define (binding to , ) and (binding to , ).

APPARENT CONSTANTS WITH A REVERSIBLE INHIBITOR

General mixed case. Competitive: . Uncompetitive: . Pure non-competitive: (), so is unchanged.

Reversible inhibition at a glance

Type

Binds

Apparent

Apparent

Lineweaver-Burk lines

Overcome by high [S]?

Competitive

E only

Unchanged

Multiplied by

Intersect on the y-axis

Yes

Uncompetitive

ES only

Divided by

Divided by the same factor

Parallel (same slope)

No

Pure non-competitive

E and ES equally ()

Divided by

Unchanged

Intersect on the x-axis at

No

Mixed

E and ES unequally

Decreases

Increases if , decreases if

Intersect left of the y-axis: above the x-axis if , below it if

No

Reading the type of inhibition from data

  1. Measure over a range of with no inhibitor and with one or more fixed .

  2. Plot against for each on one graph.

  3. Compare the y-intercepts (): unchanged means competitive.

  4. If the y-intercepts differ, compare the x-intercepts (): unchanged means pure non-competitive.

  5. Parallel lines (slope the same) mean uncompetitive; lines meeting at neither axis mean mixed.

  6. To find the inhibition constants: the Lineweaver-Burk slope with inhibitor is , which gives ; the y-intercept is , which gives . For a competitive inhibitor this is the same as ; for an uncompetitive one use .

Irreversible inhibitors bind covalently or so tightly that they effectively remove active enzyme. Examples are diisopropyl fluorophosphate (DIFP) on the active-site serine of serine proteases and acetylcholinesterase, and iodoacetamide on cysteine. They lower the amount of active enzyme, so falls, while the enzyme that stays active keeps its normal . This looks like non-competitive inhibition, but dialysis does not restore activity. A suicide (mechanism-based) inhibitor is converted by the enzyme's own catalytic cycle into a reactive species that then inactivates it.

WORKED EXAMPLE

An enzyme has M and nM/s. A single uncompetitive inhibitor at M has M. Find the velocity at M with and without the inhibitor.

Solution
  1. Without inhibitor: nM/s.

  2. , .

  3. nM/s and M.

  4. nM/s.

Answer: 100 nM/s without the inhibitor, 50 nM/s with it.

EXAM TIP

Do not match types by intuition about "strength". The surest test is the pattern of intercepts. Intersection on the y-axis means competitive, intersection on the x-axis means pure non-competitive, parallel lines mean uncompetitive.

Regulation of enzyme activity

Cells control flux through a pathway at a few key enzymes, using several mechanisms.

Regulatory mechanisms

Mechanism

Key features

Example

Allosteric regulation

Effectors bind a site other than the active site. In the concerted (all-or-none) model they shift the equilibrium between a low-affinity (T) and a high-affinity (R) state of the whole enzyme; in the sequential model subunits change one at a time. Effects of the substrate itself are homotropic, those of other molecules heterotropic. Enzymes are usually oligomeric and show sigmoidal against (cooperativity), so they do not obey Michaelis-Menten kinetics. The half-saturating concentration is written , not .

Aspartate transcarbamoylase (CTP inhibits, ATP activates); phosphofructokinase-1 (ATP and citrate inhibit, AMP and fructose 2,6-bisphosphate activate)

Feedback inhibition

The end product of a pathway inhibits an early, committed enzyme, usually allosterically

CTP inhibiting aspartate transcarbamoylase in pyrimidine synthesis

Reversible covalent modification

Attachment and removal of a group, commonly phosphate on Ser, Thr or Tyr (added by kinases, removed by phosphatases), switches activity on or off

Glycogen phosphorylase: phosphorylation converts b to the more active a

Proteolytic activation (zymogens)

An inactive precursor is irreversibly activated by cleaving a peptide

Trypsinogen to trypsin (by enteropeptidase), then chymotrypsinogen to chymotrypsin by trypsin

Isozymes

Different proteins catalysing the same reaction with different kinetic or regulatory properties, often tissue-specific

Lactate dehydrogenase has five isozymes made from H and M subunits (H to M)

HILL EQUATION FOR COOPERATIVE ENZYMES

Here . A plot of the left side against has slope , the Hill coefficient. means positive cooperativity, no cooperativity, negative cooperativity. cannot exceed the number of substrate-binding sites.

In a K-type allosteric enzyme the effector changes with unchanged (the curve shifts left or right). In a V-type enzyme the effector changes with unchanged. For a K-type enzyme in the concerted model, an allosteric activator shifts the curve to the left and makes it less sigmoidal, closer to a hyperbola. An allosteric inhibitor shifts it to the right and makes it more sigmoidal.

EXAM TIP

A sigmoidal curve rules out simple Michaelis-Menten behaviour, so a Lineweaver-Burk plot of an allosteric enzyme is curved, not a straight line. Do not quote a for such an enzyme; use .

PREVIOUS-YEAR QUESTIONS

6 questions from the BT papers

Try each question first, then open the answer. We placed each question under a topic ourselves; the exam paper does not label topics.

See these papers in full: GATE BT 2026 · GATE BT 2025 · GATE BT 2020 · GATE BT 2019

GATE 2025 BT Q.41

GATE 2025 · BTQ.41 · 2 marks · MCQ

Correctly match the Coenzyme with its respective involvement in a specific Reaction type. Coenzyme: P. Thiamine pyrophosphate; Q. Tetrahydrofolate; R. Flavin adenine dinucleotide; S. 5'-Deoxyadenosyl cobalamin. Reaction type: 1. Acyl group transfer; 2. Transfer of one carbon group; 3. Transfer of methyl group; 4. Oxidation-reduction; 5. Aldehyde transfer.

  1. (A)

    P-5; Q-2; R-4; S-3

  2. (B)

    P-5; Q-1; R-2; S-3

  3. (C)

    P-1; Q-2; R-4; S-5

  4. (D)

    P-5; Q-3; R-1; S-2

Answer and solution
See the question in the paper
GATE 2025 BT Q.41: answer and solution

GATE 2019 BT Q.14

GATE 2019 · BTQ.14 · 1 mark · MCQ

Which one of the following statements is CORRECT for enzyme catalyzed reactions? ( is Gibbs free energy change, is equilibrium constant)

  1. (A)

    Enzymes affect , but not

  2. (B)

    Enzymes affect , but not

  3. (C)

    Enzymes affect both and

  4. (D)

    Enzymes do not affect or

Answer and solution
See the question in the paper
GATE 2019 BT Q.14: answer and solution

PRACTICE

5 questions to test yourself

PRACTICE 11 mark · NAT

An enzyme has mM. What substrate concentration (in mM) is needed for the initial velocity to be 90% of ?

Answer and solution

Answer: (accepted range )

  1. .

  2. , so and .

  3. mM.

PRACTICE 22 marks · MSQ

A reversible uncompetitive inhibitor is added to an enzyme obeying Michaelis-Menten kinetics. Which of the following statements are correct?

  1. (A)

    The apparent decreases.

  2. (B)

    The apparent decreases.

  3. (C)

    Lineweaver-Burk lines with and without the inhibitor are parallel.

  4. (D)

    The inhibition can be fully overcome by a sufficiently high substrate concentration.

Answer and solution

Answer: (A), (B), (C)

  1. The inhibitor binds only ES, so both and decrease (A and B true).

  2. The ratio is unchanged, so the slope is unchanged and the lines are parallel (C true).

  3. More substrate gives more ES, which binds more inhibitor, so cannot be restored (D false).

PRACTICE 32 marks · MCQ

A purified enzyme preparation contains 10 nM total enzyme active sites. The maximum velocity is 5 M/s and M. What is the catalytic efficiency ?

  1. (A)

  2. (B)

  3. (C)

  4. (D)

Answer and solution

Answer: (C)

  1. .

  2. M.

  3. .

PRACTICE 41 mark · MCQ

The conversion of glucose 6-phosphate to fructose 6-phosphate is catalysed by an enzyme belonging to which EC class?

  1. (A)

    Oxidoreductases

  2. (B)

    Transferases

  3. (C)

    Lyases

  4. (D)

    Isomerases

Answer and solution

Answer: (D)

  1. The reaction rearranges atoms within one molecule (aldose to ketose) without adding or removing water or transferring a group to another molecule.

  2. Such intramolecular rearrangements are catalysed by isomerases (EC 5).

PRACTICE 52 marks · NAT

An enzyme follows Michaelis-Menten kinetics with mM and mol/min. In the presence of a competitive inhibitor at mM the apparent is 6 mM. Find of the inhibitor in mM.

Answer and solution

Answer: (accepted range )

  1. For a competitive inhibitor .

  2. , so .

  3. , so mM.

OFFICIAL GATE 2027 SYLLABUS WORDING

Copied from the GATE 2027 syllabus; see all 2027 syllabi.

GATE BT

Enzymes - Classification, catalytic and regulatory strategies; Enzyme kinetics - Michaelis-Menten equation; Enzyme inhibition - competitive, non- competitive and uncompetitive inhibition

Preparing in Kolkata? IAE Academy's course for GATE BT.