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GATE 2025 EE Q.61: solution and answer

GATE 2025 · EEQ.61 · 2 marks · NAT

An ideal low pass filter has frequency response given by

Let be its time domain representation. Then ______ (round off to the nearest integer).

See the question in the paper

Answer and solution

ANSWER

Official answer: 200Source: Official answer key, GATE 2025 EE (IIT Roorkee)

  1. Start from the inverse Fourier transform:

  2. Set . Then , so is the area under divided by :

  3. only for and is everywhere else. The area is therefore the width of the passband, :

  4. Check against the closed form. Using for small :

  5. The result is already a whole number, so no rounding is needed: .

KEY IDEA

The value of a signal at is the total area under its Fourier transform divided by : . For an ideal rectangular low-pass response of height 1 and cutoff , that area is , so . Here gives .

WATCH OUT FOR

Leaving out the factor gives . Taking as a frequency in hertz, or using only the positive half of the passband (width instead of ), gives . The passband runs from to rad/s, and both halves count.

From the GATE 2025 EE paper. Every question of this paper · Download the full paper · All 22 Fourier transform questions, with notes

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