Let and denote the set of real numbers and the three dimensional vector space over it, respectively. The value of for which the set of vectors
does not form a basis of is ______.
Let and denote the set of real numbers and the three dimensional vector space over it, respectively. The value of for which the set of vectors
does not form a basis of is ______.
ANSWER
The set fails to be a basis of only when . At that value the determinant is zero, and is the average of the other two vectors.
Official answer: 5Source: Official answer key, GATE 2024 EC (IISc Bengaluru)
In , three vectors form a basis exactly when they are linearly independent. So the set fails to be a basis exactly when the matrix with these vectors as its rows is singular, i.e. .
Put the vectors in as rows:
Expand the determinant along the first row (cofactor expansion):
Simplify each minor: , , . So .
For linear dependence, set : .
Check: when , . The first vector lies in the span of the other two, so the set does not form a basis of . The answer is .
KEY IDEA
Three vectors in form a basis if and only if they are linearly independent, which happens if and only if the matrix built from them has a non-zero determinant. Set the determinant to zero and solve for .
WATCH OUT FOR
Getting the sign wrong on the middle cofactor. The first-row pattern is and the entry there is , so the term is , not . With the wrong sign you get and a non-integer . Also, solving for the that makes the set a basis gives every , not one number: the question asks for the value where it is not a basis.
From the GATE 2024 EC paper. Every question of this paper · Download the full paper · All 46 Linear algebra questions, with notes