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GATE 2025 EC Q.60: solution and answer

GATE 2025 · ECQ.60 · 2 marks · NAT

and are Bernoulli random variables taking values in . The joint probability mass function of the random variables is given by: , , , . The mutual information is ________ (rounded off to two decimal places).

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Answer and solution

ANSWER

bits, because and are independent.

Official answer: 0.0Source: Official answer key, GATE 2025 EC (IIT Roorkee)

  1. Marginal of : and .

  2. Marginal of : and .

  3. Mutual information is . Each term is zero when , and exactly when this holds for every pair.

  4. Check each cell: , , , . Every product equals the given joint probability.

  5. So and are independent and every log term is . Hence bits, which is to two decimal places.

KEY IDEA

Mutual information is zero exactly when the joint PMF equals the product of its marginals. Compute the marginals and test this before doing any entropy arithmetic.

WATCH OUT FOR

Computing , and by hand and letting rounding errors leave a small non-zero value. Another slip is to take the joint probabilities as a dependent pair without checking the products of the marginals.

From the GATE 2025 EC paper. Every question of this paper · Download the full paper · All 9 Information theory questions, with notes

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